**(1) 230VAC**230VAC we know is root mean square value of sine wave voltage

**(2) Circuit**Make a circuit as following

Diode will cut-off half of power source. Resistor voltage will be half of power source, so:

**(3) Resistor calculation**Assume that, current need to flow through LED is 20mA

__(a) Value of Resistor__

__(b) Power of Resistor:__

One solution to choose Resistor with 5.6KOhm 2W

It is maybe make the Resistor hot and burn soon

So, we can divide into 2 Resistors with 2.7KOhm 2W

-> Those 2 resistors can load upto 4W

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